RE: [Axiom-developer] [Q] How to classify # integrate(log(%i+z^2), z) -> 2 ?

[Bill Page]

On Friday, February 11, 2005 9:56 AM Vladimir Bondarenko wrote:
> ... 
> ===> Case 2.
> 
> -> integrate(log(%i+z^2), z)
> 
>                   +-----+    2
>      +-----+    z\|- 4%i  + z  - %i            2
>     \|- 4%i log(-------------------) + 2z log(z  + %i) - 4z
>                        2
>                       z  + %i
>    [-------------------------------------------------------,
>                                2
>                                  +---+
>            2          +---+     \|4%i
>     z log(z  + %i) - \|4%i atan(------) - 2z]
>                                   2z
> ... 
> But why the user really needs 2 forms of the same answer?
> 

I think you should report it as a bug.

Regards,
Bill Page.