I think having a specific flag to use that disables all the input and
output magic is the correct way to go. --rawCIN does this for input.
Is there a --rawCOUT?
Regards,
Elias
On 7 February 2017 at 19:54, Juergen Sauermann
<address@hidden <mailto:address@hidden>>
wrote:
Hi Elias,
that would tell you if your stdin is a terminal. But as we have
seen below this is always
the case with zsh even if apl is called from a script. zsh behaves
exactly as if the first script line
(but without the leading #!**) was entered manually but then does
not do the same with subsequent
lines but instead keeps reading from stdin of the calling process.
/// Jürgen
On 02/07/2017 12:24 PM, Elias Mårtenson wrote:
Shouldn't you be able to simply call isatty(0) to determine this?
Regards,
Elias
On 7 February 2017 at 19:21, Juergen Sauermann
<address@hidden
<mailto:address@hidden>
<mailto:address@hidden
<mailto:address@hidden>>> wrote:
Hi Xiao-Yong,
yes, and GNU APL is doing a similar thing. However, the
problem
seems to be that the
shell is not piping the rest of the script into the stdin
of the
called interpreter, but instead
cloning its own stdin.
And according to the argv printout below, GNU APL has no
chance to
tell if it was called directly
by the shell or via an apl script. And due to that, it
behaves as
if it was called directly.
/// Jürgen
On 02/06/2017 10:03 PM, Xiao-Yong Jin wrote:
In terms of how interpreters should do with multiple
arguments in the #! line, perl's behavior is useful.
The following is from 'perldoc perlrun'
The "#!" line is always examined for switches as
the line is being parsed.
Thus, if you're on a machine that allows only one
argument with the "#!"
line, or worse, doesn't even recognize the "#!"
line, you still can get
consistent switch behaviour regardless of how
Perl was invoked, even if
-x was used to find the beginning of the program.
You may also want to read the rest of the document.
On Feb 6, 2017, at 2:06 PM, Juergen
Sauermann<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>> wrote:
Hi Xiao-Yong,
thanks a lot for this explanation!
/// Jürgen
On 02/06/2017 08:25 PM, Xiao-Yong Jin wrote:
I would guess he is using zsh instead of bash.
zsh allows interpreter after #! without an
absolute path, irrelevant of the OS kernel.
Try running the following script under zsh:
---- SCRIPT BEGIN ----
#!bash
echo 'this will fail'
---- SCRIPT END ----
You will get
---- OUTPUT BEGIN ----
bash: echo 'this will fail'
: No such file or directory
---- OUTPUT END ----
Zsh under both Linux and OSX should give this
error, because zsh is making the syscall with its
own interpretation of the shebang line.
On the other hand, with the absolute path, you
get the standard OSX kernel handling the syscall.
Google gives a detailed list of behaviors on a
webpage
http://www.in-ulm.de/~mascheck/various/shebang/
<http://www.in-ulm.de/%7Emascheck/various/shebang/>
<http://www.in-ulm.de/%7Emascheck/various/shebang/
<http://www.in-ulm.de/%7Emascheck/various/shebang/>>
Your code supporting argv[1] with a
concatenated string like '-l 37 --script --' may
not be the best practice, IMHO, and should be avoided.
Putting more than 1 argument on the shebang
line is calling for troubles if you want cross
OS/kernel support.
On Feb 6, 2017, at 12:43 PM, Juergen
Sauermann<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>> wrote:
Hi Alexey,
very odd indeed. It very much looks like
OSX is starting apl but then not piping
the subsequent lines of the script into
APL. As if they are opening the script with
popen() instead of execve(). Its probably
more a problem of the shell than of
the entire OS.
I would also believe that after starting
the script you are in immediate execution
mode in GNU APL but with input echo off
(apl was started with --script).
I suppose if you replace '--' by '-f' in
your first script line (without mentioning the
script name as I proposed earlier), then
it should work.
BTW a non-absolute path does not work in
GNU/APL, which shows how different the
platforms are in this area.
/// Jürgen
On 02/06/2017 06:45 PM, Alexey
Veretennikov wrote:
Hi!
Finally I've down to something.
So the difference is whether I specify
full path to apl in a file
header.
Consider:
head -1 aaa.apl
#!apl -l 37 --script --
sizeof(Svar_record) is 328
sizeof(Svar_partner) is 28
increasing rlimit RLIMIT_NPROC from
709 to infinity
initializing paths from argv[0] = apl
initializing paths from $PATH =
/Users/alexeyv/Applications:/Users/alexeyv/Development/stm32tools:/Users/alexeyv/Development/arm-eabi-toolchain/arm-cs-tools-2012.03-56-e3f4013-20130413/bin:/Users/alexeyv/Development/gapl:/Users/alexeyv/.cabal/bin:/Users/alexeyv/Development/gradle-2.3/bin:/Users/alexeyv/Development/groovy-2.4.3/bin:/opt/local/bin:/opt/local/sbin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/bin:/Library/TeX/texbin
APL_bin_path is:
/Users/alexeyv/Development/gapl
APL_bin_name is: apl
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/preferences
...
Reading config file
/Users/alexeyv/.gnu-apl/preferences ...
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/parallel_thresholds
...
Not reading config file
/Users/alexeyv/.config/gnu-apl/parallel_thresholds
(not found/readable)
0 input files:
using ANSI terminal output ESC
sequences (or those configured in your
preferences file(s))
using ANSI terminal input ESC
sequences(or those configured in your
preferences file(s))
Using TCP socket towards APserver...
connecting to 127.0.0.1 TCP port 16366
failed.
(the first ::connect() to
APserver is expected to fail, unless
APserver was started manually)
Starting a new APserver listening on
127.0.0.1 TCP port 16366
Found
/Users/alexeyv/Development/gapl/APserver
Starting
/Users/alexeyv/Development/gapl/APserver
--port 16366 --auto...
connecting to 127.0.0.1 TCP port 16366
failed.
(::connect() should succeed
eventually. This was attempt 1 of 5)
connecting to 127.0.0.1 TCP port 16366
failed.
(::connect() should succeed
eventually. This was attempt 2 of 5)
connecting to 127.0.0.1 TCP port 16366
failed.
(::connect() should succeed
eventually. This was attempt 3 of 5)
connecting to 127.0.0.1 TCP port 16366
failed.
::connect() to supposedly existing
APserver failed: Invalid argument
PID is 14426
argc: 3
argv[0]: 'apl'
argv[1]: '-l 37 --script --'
argv[2]: './aaa.apl'
stdin is: OPEN
uprefs.user_do_svars: 1
uprefs.system_do_svars: 1
uprefs.requested_id: 0
uprefs.requested_par: 0
Svar_DB not connected in
Svar_DB::is_registered_id()
id.proc: 1001 at ProcessorID.cc:77
Processor ID was completely
initialized: 1001:0:0
system_do_svars is: 1
┌→──────────────────────────────────────────┐
│┌→──┐ ┌→─┐ ┌→─┐ ┌→───────┐ ┌→─┐
┌→────────┐│
││apl│ │-l│ │37│ │--script│ │--│
│./aaa.apl││
│└───┘ └──┘ └──┘ └────────┘ └──┘
└─────────┘│
└∊──────────────────────────────────────────┘
However:
head -1 bbb.apl
#!/Users/alexeyv/Development/gapl/apl
-l 37 --script --
./bbb.apl
sizeof(Svar_record) is 328
sizeof(Svar_partner) is 28
increasing rlimit RLIMIT_NPROC from
709 to infinity
initializing paths from argv[0] =
/Users/alexeyv/Development/gapl/apl
initializing paths from $PWD =
/Users/alexeyv/Sources/apl
APL_bin_path is:
/Users/alexeyv/Development/gapl
APL_bin_name is: apl
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/preferences
...
Reading config file
/Users/alexeyv/.gnu-apl/preferences ...
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/parallel_thresholds
...
Not reading config file
/Users/alexeyv/.config/gnu-apl/parallel_thresholds
(not found/readable)
0 input files:
using ANSI terminal output ESC
sequences (or those configured in your
preferences file(s))
using ANSI terminal input ESC
sequences(or those configured in your
preferences file(s))
Using TCP socket towards APserver...
connected to APserver, socket is 4
using Svar_DB on APserver!
PID is 14455
argc: 6
argv[0]:
'/Users/alexeyv/Development/gapl/apl'
argv[1]: '-l'
argv[2]: '37'
argv[3]: '--script'
argv[4]: '--'
argv[5]: './bbb.apl'
stdin is: OPEN
uprefs.user_do_svars: 1
uprefs.system_do_svars: 1
uprefs.requested_id: 0
uprefs.requested_par: 0
id.proc: 1001 at ProcessorID.cc:77
Processor ID was completely
initialized: 1001:0:0
system_do_svars is: 1
- Here it hangs.
Here you see what depending on whether
we have a full path in the first
line command line arguments
interpreted differently. Very odd.
Juergen Sauermann
<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>>
writes:
Hi Alexey,
but then everything is just fine,
isn't it? I believe in an
earlier post you said that in OSX
you don't see any output and have to
type )OFF
blindly (which suggest that you
didn't have a working stdin)?
/// Jürgen
On 02/06/2017 05:53 PM, Alexey
Veretennikov wrote:
Hi,
Here are the results:
sizeof(Svar_record) is 328
sizeof(Svar_partner) is 28
increasing rlimit RLIMIT_NPROC
from 709 to infinity
initializing paths from argv[0] = apl
initializing paths from $PATH =
/Users/alexeyv/Applications:/Users/alexeyv/Development/stm32tools:/Users/alexeyv/Development/arm-eabi-toolchain/arm-cs-tools-2012.03-56-e3f4013-20130413/bin:/Users/alexeyv/Development/gapl:/Users/alexeyv/.cabal/bin:/Users/alexeyv/Development/gradle-2.3/bin:/Users/alexeyv/Development/groovy-2.4.3/bin:/opt/local/bin:/opt/local/sbin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/bin:/Library/TeX/texbin
APL_bin_path is:
/Users/alexeyv/Development/gapl
APL_bin_name is: apl
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/preferences
...
Reading config file
/Users/alexeyv/.gnu-apl/preferences ...
Reading config file
/Users/alexeyv/Development/gapl/etc/gnu-apl.d/parallel_thresholds
...
Not reading config file
/Users/alexeyv/.config/gnu-apl/parallel_thresholds
(not found/readable)
0 input files:
using ANSI terminal output ESC
sequences (or those configured in your
preferences file(s))
using ANSI terminal input ESC
sequences(or those configured in your
preferences file(s))
Using TCP socket towards APserver...
connected to APserver, socket is 4
using Svar_DB on APserver!
PID is 13743
argc: 3
argv[0]: 'apl'
argv[1]: '-l 37 --script --'
argv[2]: './aaa.apl'
stdin is: OPEN
uprefs.user_do_svars: 1
uprefs.system_do_svars: 1
uprefs.requested_id: 0
uprefs.requested_par: 0
id.proc: 1001 at ProcessorID.cc:77
Processor ID was completely
initialized: 1001:0:0
system_do_svars is: 1
┌→──────────────────────────────────────────┐
│┌→──┐ ┌→─┐ ┌→─┐ ┌→───────┐ ┌→─┐
┌→────────┐│
││apl│ │-l│ │37│ │--script│ │--│
│./aaa.apl││
│└───┘ └──┘ └──┘ └────────┘ └──┘
└─────────┘│
└∊──────────────────────────────────────────┘
Juergen Sauermann
<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>>
writes:
Hi,
i have added a check if stdin is
open when GNU APL starts, SVN 881.
If you start the following script:
#!/usr/local/bin/apl -l 37 --script --
]BOXING ¯8
⎕ARG
)off
Then we can see if stdin is open
on OSX and how apl is being called in OSX.
/// Jürgen
On 02/06/2017 11:21 AM, Juergen
Sauermann wrote:
Hi Alexey,
yes. I changed it recently to
fix the '--' issue.
A GNU APL script assumes that it
was called by execve(). The
expand_argv() function
"undoes" the behavior of
execve(), which lumps together all
arguments on the first script line
into argv[1] of GNU APL's
main(argc, argv) functions. In that
process the filename of the script
gets lost (or may not even
exist, e.g. in a pipe) so -f could be
used to tell the script where to
fetch its input. This is because
execve() had already closed the file
descriptor before it called
apl, so apl has no stdin when it
starts. With -f you point apl to
re-open the input file again.
/// Jürgen
On 02/05/2017 09:24 PM, Alexey
Veretennikov wrote:
Ok, as I understand I need to
take a look at
UserPreferences::expand_argv
and
UserPreferences::is_APL_script
correct?
Juergen Sauermann
<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>>
writes:
Hi,
yes, most of this trouble is
caused by how execve() works, which is
quite different
on different platforms. And it
happens before apl is being called so
I cant do much
about it.
Sometimes it helps to start apl
with -f so that the interpreter knows
where to fetch
its input, like:
#!/usr/local/bin/apl -f
/home/eedjsa/tmp/script --script --
/// Jürgen
On 02/04/2017 02:00 PM, Alexey
Veretennikov wrote:
Hi Juergen,
Something is apparently strange on
OSX(?). With the latest version
when I run the same script below I
get the silent input without
echoing, no output like below, and
I have to blindly type )off manually
to exit interpreter.
Juergen Sauermann
<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>>
writes:
Hi Alexey,
I have changed the handling of
command line options, SVN 877.
It now works like this:
script:
#!/usr/local/bin/apl --script --
)copy 5 FILE_IO FIO∆errno
8⎕CR ⎕ARG
)off
output:
address@hidden:~/tmp$ ./script
scriptarg
DUMPED 2017-01-28 22:57:44 (GMT+1)
┌→──────────────────────────────────────────────────────────┐
│┌→─────────────────┐ ┌→───────┐
┌→─┐ ┌→───────┐
┌→────────┐│
││/usr/local/bin/apl│ │--script│
│--│ │./script│ │scriptarg││
│└──────────────────┘ └────────┘
└──┘ └────────┘
└─────────┘│
└∊──────────────────────────────────────────────────────────┘
/// Jürgen
On 02/03/2017 11:06 PM, Alexey
Veretennikov wrote:
Hi,
Yes ./script -- myarg works.
The problem is why I have to
repeat -- in command line since I've
already specified it in the first
line of the script, as it is specified
in documentiation.
Basically I would like to pass my
arguments to the script without
mentioning "--" in the command line.
Juergen Sauermann
<address@hidden
<mailto:address@hidden>>
<mailto:address@hidden
<mailto:address@hidden>>
writes:
Hi Alexey,
how about this:
address@hidden:~/tmp$ ./script
-- arg**
**DUMPED 2017-01-28 22:57:44 (GMT+1)**
**┌→────────────────────────────────────────────────────┐**
**│┌→─────────────────┐ ┌→───────┐
┌→───────┐ ┌→─┐ ┌→──┐│**
**││/usr/local/bin/apl│ │--script│
│./script│ │--│ │arg││**
**│└──────────────────┘ └────────┘
└────────┘ └──┘ └───┘│**
**└∊────────────────────────────────────────────────────┘*
There is no point (and it does not
work) to put the arguments in the
first line
of the script,
because if the script itself knows
them then the rest of the script can
use them
as well.
*⎕ARG *is what is passed to the
script, not what is passed to the
interpreter
mentioned in the script.
See also *man execve*.
/// Jürgen
On 02/03/2017 08:29 PM, Alexey
Veretennikov wrote:
Given the following script:
------------------------------------------
#!apl --script --
)copy 5 FILE_IO FIO∆errno
8⎕CR ⎕ARG
)off
------------------------------------------
when I try to run it like
./script.apl myarg
I get the error:
/script.apl myarg
unknown option 'myarg'
...
This happens on 833 and 1.5 and on
both linux and osx.
In INFO file it explicitely states:
"Using ’—-’ as last argument on
the first line of the script file
prevents any of the options given
to the script to be interpreted as APL
options; all such options are
passed to the application via ⎕ARG."
But it is not happening.