Re: Failure of `make.test'

[Stepan Kasal]

Hello,
  to reproduce what the test does, try the following:

mkdir test.dir
cd test.dir
cat > configure.ac <<\EOF
AC_INIT(foo,0,np)
AM_INIT_AUTOMAKE(foreign)
AM_MAKE_INCLUDE
AC_OUTPUT(Makefile)
EOF
touch Makefile.am
autoreconf -i
MAKE='make -w' ./configure

In my case, the configure output contains (near the end):
checking for style of include used by make -w... GNU

But in your case, it will probably be:

> checking for style of include used by make -w... none

Attached below please find a test similar to that pefofrmed by configure.
Could you please try it?  What is the output?

Have a nice day,
        Stepan

#!/bin/sh
am_make='make -w'
cat > confinc << 'END'
am__doit:; @echo done
.PHONY: am__doit
END
# If we don't find an include directive, just comment out the code.
echo -n "checking for style of include used by $am_make... "
am__include="#"
am__quote=
_am_result=none
# First try GNU make style include.
echo "include confinc" > confmf
# We grep out `Entering directory' and `Leaving directory'
# messages which can occur if `w' ends up in MAKEFLAGS.
# In particular we don't look at `^make:' because GNU make might
# be invoked under some other name (usually "gmake"), in which
# case it prints its new name instead of `make'.
if test "`$am_make -s -f confmf 2> /dev/null | grep -v 'ing directory'`" = 
"done"; then
   am__include=include
   am__quote=
   _am_result=GNU
fi
# Now try BSD make style include.
if test "$am__include" = "#"; then
   echo '.include "confinc"' > confmf
   if test "`$am_make -s -f confmf 2> /dev/null`" = "done"; then
      am__include=.include
      am__quote="\""
      _am_result=BSD
   fi
fi
echo "$_am_result"
rm -f confinc confmf