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Wed, 03 Oct 2001 17:27:21 GMT
simple problem, but a basic problem nonetheless
echo \z #backslash is a special character to the shell, so it is not printed
echo "\z" #when using double quotes, every special character is turned off
except variable and argument substitution ($), backticks and backslash.
why does the last statement output: \z instead of (what i expected) the same
as the former command (a single z)???