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Re: bash 2.05b xargs question


From: Paul Jarc
Subject: Re: bash 2.05b xargs question
Date: Wed, 19 Mar 2003 13:59:44 -0500
User-agent: Gnus/5.090017 (Oort Gnus v0.17) Emacs/21.2 (gnu/linux)

David Pease <address@hidden> wrote:
> $ echo 1 |xargs -ip echo $[ p ] p
> 0 1
>
> Is this the correct behavior?

Yes.  The arithmetic expansion is done by bash before xargs is
executed.  $p is presumably not set, so $[p] is 0.  You can see the
arguments actually seen by xargs like this:
$ bash -xc 'echo 1 | xargs -ip echo $[ p ] p'
+ echo 1
+ xargs -ip echo 0 p
0 1

Here's how you could get the behavior you want:
echo 1 | xargs -n 1 bash -c 'echo $[$0] $0'


paul




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