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Re: Linux: bash 'declare -f' adds trailing whitespaces to output
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From: |
Chet Ramey |
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Subject: |
Re: Linux: bash 'declare -f' adds trailing whitespaces to output |
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Date: |
Tue, 25 Sep 2007 10:32:16 -0400 |
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User-agent: |
Thunderbird 2.0.0.6 (Macintosh/20070728) |
Jari Aalto wrote:
> Tested in:
>
> GNU bash, version 2.05.0(1)-release (sparc-sun-solaris2.9)
> GNU bash, version 3.2.25(16)-release (i686-pc-cygwin)
>
> An example:
>
> function testfunc ()
> {
> echo "this is test"
> }
>
> From shell:
>
> $ declare -f | grep testfunc -A 3 | cat -A
>
> Result; notice the trailing whitespaces in output:
It doesn't change the declaration or the semantics. How is it a
problem?
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
Live Strong. No day but today.
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/