Re: simple bug/compat question

[Jan Schampera]

Linda Walsh wrote:
> Am running an older bash version and this may be fixed (assuming it
> is a bug and I'm not confused...:-))
> 
> bash version = 3.2.39(20)
> 
> This works:
> 1)    if [  -n ""  -a 2 -gt 1 ] ; then echo one;fi
> 
> This does not:
> 2)    if [[  -n ""  -a 2 -gt 1 ]] ; then echo one;fi
> 
> 
> 
> Shouldn't 2 work equally well as 1?
> 
> (original test on "$1":
>     -n "$1" -a "$1" -gt 0
> )

I don't know if it should be line that, but it definitely isn't the
case. This is also (indirectly) described in the manual: There's a
section about "conditional expressions" which holds all the stuff that [
and [[ have in common, then there are individual sections for [[ and
test ([) which list &&/|| for [[ and -a/-o for test.

http://bash-hackers.org/wiki/doku.php/syntax/ccmd/conditional_expression
/-----
Do not use the test-typical operators -a and -o for AND and OR, they are
not known to the conditional expression. Instead, use the operators &&
and ||.
\-----


Ragards,
Jan

-- 
This is my life - this is my net!
- Jan