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Re: read -d'' -n1


From: Greg Wooledge
Subject: Re: read -d'' -n1
Date: Thu, 12 Aug 2010 08:19:57 -0400
User-agent: Mutt/1.4.2.3i

> On Thu, Aug 12, 2010 at 1:46 PM, Jan Schampera <address@hidden> wrote:
> >> while read -d'' -n1 ch; do

On Thu, Aug 12, 2010 at 01:50:34PM +0800, Sharuzzaman Ahmat Raslan wrote:
> Which part is the mistake, and what is the solution?

If you want the argument of -d to be an empty string, you have to separate
the empty string argument from the -d with some whitespace:

  read -d '' -n1 ch

Otherwise, -d'' is exactly the same as -d (the '' goes away entirely),
and read tries to use the -n1 as the argument of -d.  Since -d only
takes a single character, the - becomes the delimiter.



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