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BUG: echo builtin does not handle -- arguments


From: Марк Коренберг
Subject: BUG: echo builtin does not handle -- arguments
Date: Mon, 22 Nov 2010 13:33:13 +0500

in latest bash:

suppose script:

for i in "address@hidden"; do
    echo "$i"
done

if malicious user give file name "-e", empty string will be emitted to
stdout, but string "-e" should.

It will be nice if I cat write
echo -- "$i"
as many tool, such as grep, use.

Now, I replace echo "$i" with printf "%s\n" "$i", but it is
workaround, as I think.

-- 
Segmentation fault



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