Re: exit status question

[Curtis Doty]

11:30am Eric Blake said:

> On 12/20/2010 11:25 AM, Curtis Doty wrote:
> > Not exactly sure if this is a bug. But I don't understand why only the
> > first time running ((i++)) returns an error exit status.
>
> Because it follows the same semantics as 'expr', where status 1 is
> reserved for a successful run with value 0, and status 2 and above are
> reserved for errors.  This was just brought up on the list earlier this
> month:
> http://lists.gnu.org/archive/html/bug-bash/2010-12/msg00087.html
>
> and seems to be a recurring question:
> http://lists.gnu.org/archive/html/bug-bash/2010-07/msg00121.html

The workaround of using ((++i)) seems to work. Thanks for the cluebat! 
Sounds like this is a FAQ.

../C