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RE: List of keys of an associative array


From: dnade.ext
Subject: RE: List of keys of an associative array
Date: Fri, 31 Dec 2010 10:56:35 +0100

Ha. Indeed, if i use declare –A, it works.

But why is bash letting me use foo[bar]=something in the first place, if I 
don’t declare foo as an associative array ?
Maybe the bug’s here.

                D

--
Damien Nadé <dnade.ext@orange-ftgroup.com>
Astek Sud-Est pour France Télécom - FT/TGPF/OPF/PORTAIL/DOP/DEV/EAQS
Sophia Antipolis - France / Tel : 04 97 12 86 20

De : Pierre Gaston [mailto:pierre.gaston@gmail.com]
Envoyé : vendredi 31 décembre 2010 10:52
À : NADE Damien Ext DMGP/PORTAIL
Cc : bug-bash@gnu.org
Objet : Re: List of keys of an associative array


On Fri, Dec 31, 2010 at 11:38 AM, 
<dnade.ext@orange-ftgroup.com<mailto:dnade.ext@orange-ftgroup.com>> wrote:
       Hello

For regular arrays, we can get the list of keys by using the form 
${!some_array[@]}.
But this just doesn’t work for associative arrays.

${!some_associative_array[@]} is actually 0. Is that a bug ?
Is there another way to get the list of keys available in an associative array ?


$ declare -A a;a[foo]=bar;a[baz]=bux;echo ${!a[@]}
baz foo

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