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From: | L A Walsh |
Subject: | Re: possible in bash?: filter stderr of a prog & send filtered-output out on stderr leaving stdout untouched |
Date: | Tue, 06 Dec 2016 15:22:55 -0800 |
User-agent: | Thunderbird |
Andreas Schwab wrote:
{ $prog 2>&1 >&3 | grep -v "$RE_filt" >&2; } 3>&1 Andreas.
Closer to my last failed case: ( echo -n >&3 $($prog >&3 2>&1 | grep -Pv "$re" >&2 ) ) 3>&1 Had tried not putting $prog in $(), but bash didn't like the parens... At that point figured it was probably solved and asked onlist... Thanks for the added input! -l
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