gdb 5.0: no symbol 'foo' in current context

[Thomas Sevaldrud]

Hello,

I am having a problem with debugging c++ programs with gdb 5.0. I am running on
a RedHat 7.0 system, and the bug may of course be related to the non-standard
compiler shipping with this system. However, I hope someone on this list might
have heard about this problem, and hopefully know of a fix or workaround to it.

The problem is that the debugger doesn't find the contents of variables that
are inside nested scopes. For example, in the following program gdb won't print
the contents of either variables 'b' or 'c'

 int main(int argc, char** argv)
 {
  int a = 10;
  for(int i = 0; i < 10; i++)
     {
     for(int j = 0; j < 10; j++)
        {
        int b = 20;
        int c = 30;
        }
     }
 }

I compile this program with

 address@hidden [tse] 109> g++ -g -o foo foo.cpp

Then I run the debugger:

 address@hidden [tse] 110> gdb foo
 GNU gdb 5.0
 Copyright 2000 Free Software Foundation, Inc.
 GDB is free software, covered by the GNU General Public License, and you are
 welcome to change it and/or distribute copies of it under certain conditions.
 Type "show copying" to see the conditions.
 There is absolutely no warranty for GDB.  Type "show warranty" for details.
 This GDB was configured as "i386-redhat-linux"...
 (gdb) break main
 Breakpoint 1 at 0x8048532: file foo.cpp, line 3.
 (gdb) run
 Starting program: /home/tse/foo 

 Breakpoint 1, main (argc=1, argv=0xbffff0e4) at foo.cpp:3
 3       int a = 10;
 (gdb) next
 4       for(int i = 0; i < 10; i++)
 (gdb) print a
 $1 = 10
 (gdb) next 3
 9             int c = 30;
 (gdb) print b
 No symbol "b" in current context.
 (gdb) 

Here is some more info on my system:

 address@hidden [tse] 112> uname -a
 Linux sauron.si.sintef.no 2.2.16-22smp #1 SMP Tue Aug 22 16:39:21 EDT 2000 
i686 unknown

 address@hidden [tse] 113> g++ --version
 2.96


If a variable is declared between the scopes here, such as in the following
code, all variables are found without problems. 

 int main(int argc, char** argv)
 {
  int a = 10;
  for(int i = 0; i < 10; i++)
     {
     int b = 20;
     for(int j = 0; j < 10; j++)
        {
        int c = 30;
        }
     }
 }


I am not subscribed to the mailing list, so please CC the answer to my email
address.


Regards,
Thomas Sevaldrud