bug#18059: 24.3.92; defvar and special variables

[Noam Postavsky]

Michael Heerdegen <michael_heerdegen@web.de> writes:

>>     (lambda ()
>>       (defvar x))

> That defvar doesn't get evaluated, or do I miss something?

Oops, you are absolutely correct.  After putting a funcall around that,
I see the same behaviour with lambda and let (i.e., both only scope the
defvar if there is at least one variable bound), both interpreted and
compiled.