Gawk 3.1.4 copyright date problem

[Paul Eggert]

The behavior I see is this:

  $ gawk --version | sed 2q
  GNU Awk 3.1.4
  Copyright (C) 1989, 1991-2003 Free Software Foundation.

The date should be "2004".  While we're on the subject, the GNU coding
standards say that in --version output the "copyright notice only
needs to mention the most recent year in which changes were
made---there's no need to list the years for previous versions'
changes."

Here's a patch.

2004-08-24  Paul Eggert  <address@hidden>

        * main.c (copyleft): Output only the most recent copyright year,
        as per the GNU coding standards.  Update year to 2004.

diff -pru gawk-3.1.4/main.c gawk-3.1.4-copyright/main.c
--- gawk-3.1.4/main.c   2004-07-28 06:42:19 -0700
+++ gawk-3.1.4-copyright/main.c 2004-08-24 10:35:52 -0700
@@ -682,7 +682,7 @@ static void
 copyleft()
 {
        static const char blurb_part1[] =
-         N_("Copyright (C) 1989, 1991-%d Free Software Foundation.\n\
+         N_("Copyright (C) %d Free Software Foundation.\n\
 \n\
 This program is free software; you can redistribute it and/or modify\n\
 it under the terms of the GNU General Public License as published by\n\
@@ -701,7 +701,7 @@ along with this program; if not, write t
 Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA  02111-1307, 
USA.\n");
  
        /* multiple blurbs are needed for some brain dead compilers. */
-       printf(_(blurb_part1), 2003);   /* Last update year */
+       printf(_(blurb_part1), 2004);   /* Last update year */
        fputs(_(blurb_part2), stdout);
        fputs(_(blurb_part3), stdout);
        fflush(stdout);