Semicolon is not treated properly in awk 3.1.4

[Alex Potanin]

Hello,

The following happens on 3.1.3 (RH Linux):

zardoz 3 % awk '{ print substr($0, 0, length($0) - 6) } '
JavaMonitorImpl_2_fire_4983_code;
JavaMonitorImpl_2_fire_4983
JavaMonitorImpl_2_fire_4983_code\;
JavaMonitorImpl_2_fire_4983_

The following happens on 3.1.4 (Debian Linux):

address@hidden:~/Purdue/ [snip]$ awk '{ print substr($0, 0, length($0) - 
6) } '
JavaMonitorImpl_2_fire_4983_code
JavaMonitorImpl_2_fire_49
JavaMonitorImpl_2_fire_4983_code\;
JavaMonitorImpl_2_fire_4983

The behavour in 3.1.4 is a bug, I beleive. :-)

Thanks,
Alex.

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Alex Potanin
PhD Student
SMCS, VUW

Office: +64 (4) 463 5302
Mobile: +64 (21) 737 654

http://www.mcs.vuw.ac.nz/~alex/
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