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[Discuss-gnuradio] something about forecast()


From: xianda
Subject: [Discuss-gnuradio] something about forecast()
Date: Wed, 4 Jun 2014 14:22:51 +0800 (CST)

Hi all:
         I want to know something about the forecast().
         I have already known that forcast() can tell  scheduler how many input items are required for each output item.
     1.But now i have read two example:
        The first one:
                       void your_block::forecast(int noutput_items,gr_vector_int &ninput_items_required){
                                    ninput_items_required[0]=100 * noutput_items;
ninput_items_required[1]=100 * noutput_items; }         
I have already understand it.
But the second one:
void forecast (int noutput_items, gr_vector_int &ninput_items_required) { unsigned ninputs = ninput_items_required.size (); for (unsigned i = 0; i < ninputs; i++) ninput_items_required[i] = 1;}
I can't understand since we can't know how many input items we required,why use ninput_items_required.size ().Can someone help me?
2.I want to know if we use the general_work().Is it means that we must use the forcast()?Thanks.
Best regards





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