Re: [Discuss-gnuradio] PMT Oddities

[Martin Braun]

I'd agree that your code is not behaving as expected. Don't have
something off the top of my head though :/

M

On 12/13/2016 02:51 PM, Dave NotTelling wrote:
> Assuming that is reproducible, does anyone have suggestions on how to
> get around it?
> 
> On Fri, Dec 9, 2016 at 9:16 PM, Dave NotTelling <address@hidden
> <mailto:address@hidden>> wrote:
> 
>     Here is a full example:
> 
>     [code]
> 
>     #!/usr/bin/python
> 
>     import pmt
> 
>     d = pmt.make_dict()
>     d = pmt.dict_add(d, pmt.intern('a'), pmt.intern('a'))
>     d = pmt.dict_add(d, pmt.intern('b'), pmt.intern('b'))
>     d = pmt.dict_add(d, pmt.intern('c'), pmt.intern('c'))
> 
>     a = pmt.cons(d, pmt.make_u8vector(10, 10))
> 
>     print 'dict_keys with a populated dictionary'
>     print pmt.dict_keys(a)
> 
>     a = pmt.cons(pmt.make_dict(), pmt.make_u8vector(10, 10))
> 
>     print 'dict_keys with an empty dictionary'
>     print pmt.dict_keys(a)
> 
>     [/code]
> 
>     You end up with the following output:
> 
>     [output]
> 
>     dict_keys with a populated dictionary
>     ((c . c))
>     dict_keys with an empty dictionary
>     Traceback (most recent call last):
>       File "test.py", line 18, in <module>
>         print pmt.dict_keys(a)
>       File "/usr/local/lib/python2.7/dist-packages/pmt/pmt_swig.py",
>     line 3010, in dict_keys
>         return _pmt_swig.dict_keys(dict)
>     RuntimeError: pmt_car: wrong_type : ()
> 
> 
>     [/output]
> 
>     The first call to dict_keys(a) returns the last element in the
>     dictionary.  The second call errors out.  Both should error out correct?
> 
>     On Fri, Dec 9, 2016 at 9:11 PM, Dave NotTelling <address@hidden
>     <mailto:address@hidden>> wrote:
> 
>         I understand that it should bomb, but it doesn't if there are
>         elements in the dictionary of the pair generated by cons.
>          that's the problem.  calling dict_keys should die on both
>         tests, but returns just fine on the first test. 
> 
> 
>         On Dec 9, 2016 1:35 PM, "Martin Braun" <address@hidden
>         <mailto:address@hidden>> wrote:
> 
>             On 12/05/2016 01:56 PM, Dave NotTelling wrote:
>             > Marcus & Martin:
>             >
>             >      I tried the dict_keys() method of checking, but even
>             that can
>             > fail.  Here is an example:
>             >
>             > [code]
>             >
>             > import pmt
>             >
>             > d = pmt.make_dict()
>             > d = pmt.dict_add(d, pmt.intern('a'), pmt.intern('a'))
>             > d = pmt.dict_add(d, pmt.intern('b'), pmt.intern('b'))
>             > d = pmt.dict_add(d, pmt.intern('c'), pmt.intern('c'))
>             >
>             > a = pmt.cons(d, pmt.make_u8vector(10, 10))
>             >
>             > print pmt.dict_keys(a)
>             >
>             > [/code]
>             >
>             > You end up with: ((c . c))
>             >
>             > The dict_keys() method will bomb if there are no elements
>             in the dictionary:
>             >
>             > print pmt.dict_keys(pmt.cons(pmt.make_dict(),
>             pmt.make_u8vector(10, 10)))
> 
>             It's supposed to bomb -- pmt.cons() does not return a dict.
>             That's
>             exactly how you can test for dicts.
> 
>             See:
>             
> https://github.com/gnuradio/gnuradio/blob/1e8562c8d5430667b48fced2d2e50ab5771dfb5e/gr-uhd/lib/usrp_block_impl.cc#L486-L494
>             
> <https://github.com/gnuradio/gnuradio/blob/1e8562c8d5430667b48fced2d2e50ab5771dfb5e/gr-uhd/lib/usrp_block_impl.cc#L486-L494>
> 
>             -- M
> 
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> 
> 
> 
>