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From: | Kyeong Su Shin |
Subject: | Re: [Discuss-gnuradio] OOT sourcec block in python error |
Date: | Tue, 31 Jul 2018 00:55:15 +0000 |
Hello Ayaz,
If you are getting 'Template error' messages, you will have to check the XML file of your block (in grc directory).
Also, 'input' is not a valid variable name in Python, as it is used for other purposes. You will have to re-name that variable to something else.
Finally, "out[0][:] = self.input" should become "out[:] = self.input" as you already selected output port and you are not outputting vectors.
Regards, Kyeong Su Shin
보낸 사람: Ayaz Mahmud <address@hidden> 대신 Discuss-gnuradio <discuss-gnuradio-bounces+address@hidden>
보낸 날짜: 2018년 7월 31일 화요일 오전 2:22:35 받는 사람: address@hidden 제목: [Discuss-gnuradio] OOT sourcec block in python error Hi,
I am trying to build a source block in python. Below is my code. After using the block I am getting a syntax error: self.Span_SourceBlock_0 = Template error: Span.SourceBlock($input)
My block should take input from user(int/float), and output the same. Though these are available blocks in GnuRadio but I am trying to learn on building it. Can you please check if my way of writing the code is correct?
import numpy from gnuradio import gr
class SourceBlock(gr.sync_block): """ docstring for block SourceBlock """ def __init__(self, input): self.input = input gr.sync_block.__init__(self, name="SourceBlock", in_sig=None, out_sig=[numpy.float32])
def work(self, input_items, output_items): out = output_items[0] out[0][:] = self.input return len(output_items[0])
Thanks, Ayaz |
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