Re: What happens when I evaluate the call the second time?

[Lennart Borgman (gmail)]

Andreas Schwab wrote:
> "Lennart Borgman (gmail)" <address@hidden> writes:
>
> > Andreas Schwab wrote:
> > > "Mathias Dahl" <address@hidden> writes:
> > >
> > > > > First C-x C-e after the function, then twice after calling it. The
> > > > > output is:
> > > > > average
> > > > > 2
> > > > > 2 (#o2, #x2, ?\C-b)
> > > > >
> > > > > Now what's the (#o2, #x2, ?\C-b) stuff?
> > > > Different ways to express 2 I think. What I find strange however, is
> > > > that it is only displayed at the second invocation of C-x C-e. 
> > > It's a feature, see eval-expression-print-format.
> > I think the thing Erik is asking about is why the output is different in
> > the second evaluation.
>
> That's the feature.  You get the verbose output with the second try.

Thanks, I see. But eval-expression-print-format does not tell about this 
AFAICS, or?