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Re: how having the basename of a file or directory
From: |
Karl Fogel |
Subject: |
Re: how having the basename of a file or directory |
Date: |
Mon, 31 Jan 2011 11:43:23 -0500 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/24.0.50 (gnu/linux) |
I think Thierry's point is that it would be useful for Emacs to have a
function called "basename", that does what functions of similar name do
in other programming language standard libraries and in the shell.
FWIW, I agree. Many times I've done an Apropos search on "basename",
only to remember that there's some complicated recipe involving
`file-name-nondirectory' (which I then go look up).
Now, what the exact behavior of `basename' should be is open to debate.
Perhaps it should be:
(defun basename (path)
(file-name-nondirectory (directory-file-name path)))
Or perhaps it should be:
(defun basename (path)
(thing-thierry-recently-defined))
Or perhaps something else.
Can we treat the two questions separately, though? If we agree that
having something called `basename' in Emacs Lisp would be good, then we
can probably quickly agree on exactly how it should behave, so let's
start with the first question: should we have `basename'?
-Karl
Thierry Volpiatto <address@hidden> writes:
>Stefan Monnier <address@hidden> writes:
>
>>> Yes thanks, that's work too, but it would be nice to do not have to take
>>> care of that:
>>
>>> (file-name-nondirectory "path/to/a/directory")
>>> should return ==> directory
>>
>> It does.
>>
>>> (file-name-nondirectory "path/to/a/file")
>>> should return ==> file
>>
>> It does.
>>
>>> So modifying `file-name-nondirectory' or creating a basename function
>>> or macro like:
>>
>>> (defun basename (fname)
>>> (if (file-directory-p fname)
>>> (let ((dirname (directory-file-name fname)))
>>> (file-name-nondirectory dirname))
>>> (file-name-nondirectory fname)))
>>
>> That won't work on (basename "/non/existing/thing/").
>> You really want to use (file-name-nondirectory (directory-file-name fname))
>Indeed, yes, thanks Stefan, but something like
>
>
>(defun basename (fname)
> (if (or (file-directory-p fname)
> (string-match "/$" fname))
> (let ((dirname (directory-file-name fname)))
> (file-name-nondirectory dirname))
> (file-name-nondirectory fname)))
>
>would work and be useful.
- how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31
- how having the basename of a file or directory, Stephen J. Turnbull, 2011/01/31
- Re: how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31
- Re: how having the basename of a file or directory, Andreas Schwab, 2011/01/31
- Re: how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31
- Re: how having the basename of a file or directory, Andreas Schwab, 2011/01/31
- Re: how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31
- Re: how having the basename of a file or directory, Andreas Schwab, 2011/01/31
- Re: how having the basename of a file or directory, Stefan Monnier, 2011/01/31
- Re: how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31
- Re: how having the basename of a file or directory,
Karl Fogel <=
- Re: how having the basename of a file or directory, Stefan Monnier, 2011/01/31
- Re: how having the basename of a file or directory, Thierry Volpiatto, 2011/01/31