[Gzz-commits] gzz/doc/pegboard/1008 PEG_1008.rst

[Tuomas J. Lukka]

CVSROOT:        /cvsroot/gzz
Module name:    gzz
Changes by:     Tuomas J. Lukka <address@hidden>        02/10/06 14:48:56

Modified files:
        doc/pegboard/1008: PEG_1008.rst 

Log message:
        twid

CVSWeb URLs:
http://savannah.gnu.org/cgi-bin/viewcvs/gzz/gzz/doc/pegboard/1008/PEG_1008.rst.diff?tr1=1.11&tr2=1.12&r1=text&r2=text

Patches:
Index: gzz/doc/pegboard/1008/PEG_1008.rst
diff -c gzz/doc/pegboard/1008/PEG_1008.rst:1.11 
gzz/doc/pegboard/1008/PEG_1008.rst:1.12
*** gzz/doc/pegboard/1008/PEG_1008.rst:1.11     Sun Oct  6 12:29:39 2002
--- gzz/doc/pegboard/1008/PEG_1008.rst  Sun Oct  6 14:48:56 2002
***************
*** 4,11 ****
  =============================================================
  
  :Authors:  Tuomas Lukka, Benja Fallenstein
! :Date:     $Date: 2002/10/06 16:29:39 $
! :Revision: $Revision: 1.11 $
  :Status:   Incomplete
  
  
--- 4,11 ----
  =============================================================
  
  :Authors:  Tuomas Lukka, Benja Fallenstein
! :Date:     $Date: 2002/10/06 18:48:56 $
! :Revision: $Revision: 1.12 $
  :Status:   Incomplete
  
  
***************
*** 29,38 ****
  
  The solution is to pass nothing about what should be done to the width
  of the string, but simply the unit square of the font. I.e.: the
! font will render itself with baseline at (0,1), and the line height
! such that the line above would have its baseline at (0,0).
! 
!     (Benja:) Ummm... *why*?
  
  The font will have its normal aspect ratio if the unit vectors 
  are equal, i.e. if the distances (0,1)..(0,0) and (0,1)..(1,1) are the same.
--- 29,37 ----
  
  The solution is to pass nothing about what should be done to the width
  of the string, but simply the unit square of the font. I.e.: the
! font will render itself with baseline somewhere between y=1 and y=0, and 
! the line height such that the similar line rendered above would have its 
! y=1 coordinate at this vob's y=0.
  
  The font will have its normal aspect ratio if the unit vectors 
  are equal, i.e. if the distances (0,1)..(0,0) and (0,1)..(1,1) are the same.