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Re: [Help-bash] inconsistency in expansions

From: Greg Wooledge
Subject: Re: [Help-bash] inconsistency in expansions
Date: Mon, 7 May 2012 09:12:04 -0400
User-agent: Mutt/

On Mon, May 07, 2012 at 07:09:15AM -0600, Bill Gradwohl wrote:
> > ${$x} isn't a valid expansion, so it throws an error, the pattern isn't
> > matched, and nothing happens.
> I see it produces an error, but I still don't see why. If $x expands to 3
> why don't I get ${3} and then the expansion of ${3}? Why is it illegal?
> What bash rule makes it so?

The definition of parameter expansion:


$x is not a valid parameter.  x is a valid parameter.  3 is a valid
parameter.  $x is not.  Therefore you cannot write ${$x}.

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