Re: [Help-bash] Clarify the meaning of 's' in $- and the meaning of -s when invoking bash

[Cristian Zoicas]

Stephane Chazelas wrote:
> 2017-03-16 08:27:53 +0100, address@hidden:
> [...]
> > It seems to me that the 's' flag is supposed to be shown in $- when
> > bash reads  the standard input. Such  a case occur when  bash is invoked
> > with the -s option. Example:
> >
> >      $ echo 'echo $-' | bash -s
> >      hBs
> >
> > However,  bash reads  the standard  input also  when there  are no  more
> > arguments  after option  processing.  Example
> >
> >     $ echo 'echo $-' | bash
> >     hB
> [...]
>
> That was a non-conformance (or at least deviation from every
> other Bourne-like shell) of bash. It was fixed in 4.4
>
> $ echo 'echo $- $BASH_VERSION' | bash
> hBs 4.4.11(1)-release
>
> IIRC, that was discussed last year either on the Austin group or
> bug-bash mailing list.

Stephane, thank you for your prompt reply.
Cristian