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LALR : How it work during parsing time with empty rule ? what to do to t
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From: |
Baldurien (club internet) |
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Subject: |
LALR : How it work during parsing time with empty rule ? what to do to the stack? |
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Date: |
Mon, 12 Sep 2005 23:31:42 +0200 |
Hello,
I've made a little parser in PHP based on bison output file, and I
experiment a little problem :
When I have to reduce, saying by rule X : Y '+' X I know I have to pop
3 times, but what happens when the rule is simply X : /* empty */ ? I
can't pop at all, so what should I do?
- LALR : How it work during parsing time with empty rule ? what to do to the stack?,
Baldurien (club internet) <=