Re: Operator precedence with empty operator

[Hans Aberg]

On 23 Mar 2010, at 22:32, Пётр Прохоренков wrote:

> Thanks for the quick reply!

You are welcome.

> Hugs code hepled. (That is weird how they never use bison precedence  
> annotations and just use multiple levels of non-terminals.)

Think of isn't the function expression rule a bit too general.

In
> expr: expr '+' expr
>   | expr '-' expr
> // Other operators...
>   | expr expr
>   | const
>   | id
>   ;

instead have
  expr: func expr
so that not every expression can serve as function identifier.

  Hans