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Re: elisp: how to pass a list argument to defun
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From: |
Tassilo Horn |
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Subject: |
Re: elisp: how to pass a list argument to defun |
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Date: |
Wed, 28 Jun 2006 12:03:37 +0200 |
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User-agent: |
Gnus/5.110006 (No Gnus v0.6) Emacs/22.0.50 (gnu/linux) |
"lalit mohan tripathi" <lalit.tripathi@gmail.com> writes:
Hi!
> (defun process-list-fn (list02, a, b, c)
> "This function prints the list02, a, b, c."
> (print list02)
> (print a)
> (print b)
> (print c))
>
> (setq list01 '("abc" "def" "xyz"))
> (process-list-fn list01 10 20 30)
>
> But I get the following error:
>
> Debugger entered--Lisp error: (void-variable list02)
Lisp doesn't know the variable `list02', but it knows `list02,'. ;-)
In Lisp you don't separate the parameters with comma. Remove them and
you'll be fine.
Bye,
Tassilo
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