Re: recognizing "end" correctly in Octave mode

[Markus Triska]

Nicolas Neuss <lastname@mathematik.uni-karlsruhe.de> writes:

> This is how Octave mode wants to indent:
>
> function A = LR3 (A0)
>   A=A0;
>   m=rows(A); n=columns(A);
>   for i=1:min(m,n)
>     A(i+1:m,i)=A(i+1:m,i)/A(i,i);
>     A(i+1:m,i+1:n) = A(i+1:m,i+1:n)-A(i+1:m,i)*A(i,i+1:n);
>     end
>     end

indent-region on this gives:

function A = LR3 (A0)
  A=A0;
  m=rows(A); n=columns(A);
  for i=1:min(m,n)
    A(i+1:m,i)=A(i+1:m,i)/A(i,i);
    A(i+1:m,i+1:n) = A(i+1:m,i+1:n)-A(i+1:m,i)*A(i,i+1:n);
  end
end

in GNU Emacs 22.0.90.10.

All the best,
Markus Triska