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Re: Mysterious hidden end of line characters.


From: Thierry Volpiatto
Subject: Re: Mysterious hidden end of line characters.
Date: Mon, 04 Feb 2008 14:00:01 +0100
User-agent: Gnus/5.13 (Gnus v5.13) Emacs/23.0.60 (gnu/linux)

Peter Dyballa <address@hidden> writes:

> Am 31.01.2008 um 11:20 schrieb Thierry Volpiatto:
>
>> The problem is when locale is french or else maybe, the regex that
>> match "Mot de passe :" don't exist.
>
> Could be this works:
>
>       "\\(\\(\\(Enter \\|[Oo]ld \\|[Nn]ew \\|'s \\|login \\|Kerberos
> \\|
> CVS \\|UNIX \\| SMB \\|LDAP \\|\\[sudo] \\|^\\)[Pp]assword\\( (again)\
> \)?\\|pass phrase\\|\\(Enter \\|Repeat \\|Bad \\)?[Pp]assphrase\\)\\
> (?:, try again\\)\\|Mot de passe \\)?\\(?: for [^:]+\\)?:\\s *\\'"
>
>
> It's a very complicated structure that takes into account that you
> might fail to enter correctly a Kerberos, or CVS, or SMB, or LDAP
> password, some pass phrase, and I don't know what else.
>
> Forgetting all this troublesome stuff, just describe another option
>
>       \\|Mot de passe
>
> with a final SPC that is then followed by
>
>       ?\\(?: for [^:]+\\)
>
> so you have to put everything before this expression into a froup with
> \\(...\\). Or this is more correct?
>
>       "\\(\\(\\(Enter \\|[Oo]ld \\|[Nn]ew \\|'s \\|login \\|Kerberos
> \\|
> CVS \\|UNIX \\| SMB \\|LDAP \\|\\[sudo] \\|^\\)[Pp]assword\\( (again)\
> \)?\\|pass phrase\\|\\(Enter \\|Repeat \\|Bad \\)?[Pp]assphrase\\)\\
> (?:, try again\\)?\\(?: for [^:]+\\)\\|Mot de passe \\)?:\\s *\\'"
>
> Mostly guessing, not completely understanding.

Finally, i found the best solution, without modifying the regex:
Just set in .bashrc an alias ==> alias su="LC_ALL su -l"
Like that the prompt is password, is hidden and when you are root,
if you do echo $LC_ALL, the env variable is unchanged (-l option of su)
fr_FR.UTF-8 for me.
Thats much more safe than modifying the comint regex.

-- 
A + Thierry
Pub key: http://pgp.mit.edu




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