Re: Optimal emacs shell for coding

[Eli Zaretskii]

> Date: Tue, 12 Aug 2008 21:02:21 +0200
> From: "Lennart Borgman (gmail)" <lennart.borgman@gmail.com>
> CC: help-gnu-emacs@gnu.org
> 
> Eli Zaretskii wrote:
> >> Date: Tue, 12 Aug 2008 20:40:35 +0200
> >> From: "Lennart Borgman (gmail)" <lennart.borgman@gmail.com>
> >> CC: help-gnu-emacs@gnu.org
> >>
> >> Eli Zaretskii wrote:
> >>>> Date: Tue, 12 Aug 2008 14:06:02 +0200
> >>>> From: "Lennart Borgman (gmail)" <lennart.borgman@gmail.com>
> >>>> CC: help-gnu-emacs@gnu.org
> >>>>
> >>>> If you look carefully at the output you can see that what is not handled 
> >>>> is the parameters to "ls". If you try "ls -1" it will work.
> >>> What "parameters to ls"?  "ls" was invoked without any parameters.
> >> If you from a shell do
> >>
> >>    ls | grep
> >>
> >> then normally ls implicitly gets the -1 parameter
> > 
> > No, it doesn't.  Please try and see for yourself (I just did).
> 
> 
> We are miscommunicating.

Maybe you are; I am not ;-)

> I am saying that if I from a shell outside of Emacs do
> 
>    ls
> 
> than I get several files listed on each row while the output from
> 
>    ls | grep some-file
> 
> implies that ls got the implicit argument -1 when used in the pipe.

And I'm saying that you are wrong: -1 is not implied in a pipeline
from the shell prompt, either.  Please try that and see for yourself.
I tried that both on GNU/Linux and in a Windows command prompt window,
and GNU `ls' does not imply -1 in either case.