On Monday 20 December 2004 18:14, you wrote:
Double dollar sign causes a single dollar sign literal to be present
in the string. I don't think that is what you want here.
Yes, but that dollar sign is accompanied by a left parenthesis, digit
and a right parenthesis. I'd assume this character sequence to be
replaced with positional argument when this string is passed as $(0)
to the $(call). I mixed in comments to illustrate the way I assumed
the evaluation should happen. Please point me to the line where I
made a mistake.
X = echo
A = $($(1)) $$(1) $$(2)
# $(0) = "$($(1)) $$(1) $$(2)"
# $(1) = X
# -> B = "echo $(1) $(2)"
B := $(call A,X)
# should be the same string as $(B), right ?
C = echo $(1) $(2)
all:
# $(0) = "echo $(1) $(2)"
# $(1) = "hi"
# $(2) = "lo"
# -> $(call B,hi,lo) should be "echo hi lo",
# but instead is "echo $(1) $(2)"
@echo '[$(call B,hi,lo)]'
# $(0) = "echo $(1) $(2)"
# $(1) = "hi"
# $(2) = "lo"
# -> $(call B,hi,lo) is "echo hi lo", as it should be.
@echo '[$(call C,hi,lo)]'
> On Mon, Dec 20, 2004 at 05:56:33PM +0300, Alexey Neyman
wrote:
Well, I'll use it, thanks. However, it seems that it's actually a
workaround. Perhaps this Makefile will illustrate better what I
mean:
<<<<
X = echo
A = $($(1)) $$(1) $$(2)
B := $(call A,X)
C = echo $(1) $(2)
$(warning "$(value B)")
$(warning "$(value C)")
all:
@echo '[$(call B,hi,lo)]'
@echo '[$(call C,hi,lo)]'
Note that the $(warning)s show that the values of B and C are the
same. Yet, the results of echo differ:
Makefile:6: "echo $(1) $(2)"
Makefile:7: "echo $(1) $(2)"
[echo $(1) $(2)]
[echo hi lo]
On Monday 20 December 2004 16:33, you wrote:
Perhaps the following modifications get you what you want. I
think
perhaps you are just missing the passthrough for the numbered
parameters
for B.
X = echo
A = $($(1)) $(2) $(3)
B = $(call A,X,$(1),$(2))
all:
@echo '[$(B)]'
@echo '[$(call B,hi,lo)]'
$(call B,hi,lo)
Ken
On Mon, Dec 20, 2004 at 01:40:02PM +0300, Alexey Neyman wrote:
Hi,
address@hidden:~/tmp> cat Makefile
X = echo
A = $($(1)) $$(1) $$(2)
B = $(call A,X)
all:
@echo '[$(B)]'
@echo '[$(call B,hi,lo)]'
address@hidden:~/tmp> make all
[echo $(1) $(2)]
[echo $(1) $(2)]
I thought the "$(call B,hi,lo)" should have evaluated to "echo
hi
lo",
shouldn't it?
Regards,
Alexey.
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