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SOLVED Re: @echo name1 = $(name1) does not work

From: Morten Gulbrandsen
Subject: SOLVED Re: @echo name1 = $(name1) does not work
Date: Sun, 29 Jan 2006 15:03:52 +0100
User-agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.7.8) Gecko/20050927 Debian/1.7.8-1sarge3

Eric West wrote:

Your include file, contains targets. When you run make without out explicit targets, the first target (implicit target) in your make file is used. In this case, the first target due to the include statement is helloworld. If you create an empty or explicitly call the "all" target, ("make all") then the code will work as you might have expected.


It works.

my fault. Tanks!



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