Re: how to filter-out a word sequence?

[Philip Guenther]

On 1/4/07, David Boyce <address@hidden> wrote:
...
>   The problem is that occasionally a target will need one of these
> removed as a special case. But of course using $(filter-out -z
> foo,...) will remove *all* the -z flags, leaving the other keywords
> hanging there alone, while quoting the string like $(filter-out "-z
> foo",...) doesn't match anything. Does anybody know a reasonable way
> to remove a whitespace-containing string?

Option 1)
   don't put a space between the -z and its argument to begin with, then use
   $(filter-out)

Option 2)
  don't put the unwanted arguments in the general variable but rather keep them
  in another variable for use with just those targets that need them

Option 3)
   $(subst -z foo,,$(args))
   ...but that fails if there are multiple spaces or a tab between
the -z and 'foo'

Option 4)
   $(subst -z foo,,$(strip $(args))
   ...but that replaces *all* internal whitespace in $(args) with single spaces


Philip Guenther