Re: Nested calls in make

[kalyan]

Hi,
I will explain the context.
I have a build system which has inter-dependencies between modules.
So for building a module i hope to write a single function which uses a single argument,namely, the module name:

define build_module
        MODULE_NAME=$(1); \
        $(do_some_sanity_checks); \
        echo building module $$MODULE_NAME; \
        for dep in `extract_dependencies_of_the_module`;do \
                $(call build_module,$$dep); \
        done; \
        $(do_build)
endef

My hope being, the module which has no dependencies builds first and so on..But it does not achieve what is intended.

Any hints are greatly appreciated.

regards
kalyan

On Tue, Nov 25, 2008 at 4:25 PM, Boris Godin <address@hidden> wrote:

The make tries to expand the function (which in this case is infinite), that's why you can't see any output.
But... what are you trying to do? You should be more specific.

kalyan wrote:

Hi
I would assume it goes to infinite loop. But what happens to "echo $(1)" . I get nothing on the console :(

regards
kalyan

On Tue, Nov 25, 2008 at 2:18 PM, Philip Guenther <address@hidden> wrote:

On Tue, Nov 25, 2008 at 12:43 AM, kalyan <address@hidden> wrote:
> I am using make-3.81.
> The GNU make manual says "The call function can be nested. Each recursive
> invocation gets its own local values for $(1), etc. that mask the values of
> higher-level call."
>
> I have tried this code but it gets stuck forever:
> -----------
> define test_function
>         echo $(1)
>         $(call test_function,1)
> endef
> all:
>         @$(call test_function,1)
> ------------

Yep, that's the correct behavior.  Apparently that's not what you
expected from the text.  It would be easier to correct your
understanding if you were to explain how you thought that snippet
would behave.


Philip Guenther

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