Re: Different compilation based on filename

[Christian Rogsch]

All,

thanks for your help. I tried both versions, the version from Cheng an 
this one. I decided to use Chengs suggestion, thus I'm not the only 
developer in this project and I found Chengs version better 
understandable for "non makefile specialists". But the other suggestions 
works as well!

Thanks again for all your help.

Regards,
Christian

Paul Smith schrieb:
> On Thu, 2009-09-10 at 14:50 +0200, Christian Rogsch wrote:
> > I have the following problem with a makefile: I want to compile files 
> > with different compiler flags, based on the name of the file.
>
> There are a number of ways to do this.  One is target-specific
> variables, as Cheng suggested.
>
> Another is constructed variable names.  Variable names in make can
> consist of other variables.  So you could do something like this:
>
>         foo.o_CFLAGS = -g
>
>         %.o : %.c
>                 $(CC) $(CFLAGS) $(address@hidden) -o $@ -c $<
>
> The $(address@hidden) (or, equivalently, $($(@)_CFLAGS)) expands to the value
> contained in the variable named by concatenating the target ($@) with
> the string _CFLAGS.
>
> Personally I find this method the most aesthetically pleasing, mainly
> because in my complex make environments I like to have all the "user
> visible" makefile purely data-driven: they simply declare variables but
> never need to declare rules.  The rules are all created in some deeply
> magical common makefiles set up for the project.
>
>
> The final way to do it is with $(eval ...) but this is overkill for this
> problem, 99% of the time.

--
Dipl.-Ing. Christian Rogsch

Bergische Universität Wuppertal
Fachbereich D, Abteilung Bauingenieurwesen
Lehr- und Forschungsgebiet Baustofftechnologie und Brandschutz
Pauluskirchstraße 7
Gebäude HF
Raum HF 24
42285 Wuppertal
Tel:    +49 (0) 202 439 4241
Fax:    +49 (0) 202 8 25 60
www.btbs.uni-wuppertal.de

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