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Re: How does $(error) work?
From: |
Paul Smith |
Subject: |
Re: How does $(error) work? |
Date: |
Thu, 09 Dec 2010 09:05:02 -0500 |
On Wed, 2010-12-08 at 14:20 -0500, Chris Cross wrote:
>
> Trying to understand how $(error) works. The manual says "error is
> generated whenever this function is evaluated." With the makefile below I
> would expect to see output from line1 of the recipe but only see output
> from $(error).
> # error.mk
> .PHONY: target
>
> target:
> @echo recipe line 1
> $(error debug exit recipe line 2)
>
> $ make -f error.mk
> error.mk:5: *** debug exit recipe line 2. Stop.
That's because make evaluates the entire recipe just before it starts
the first line of the recipe; it doesn't evaluate the lines one at a
time as it's about to execute that line.
--
-------------------------------------------------------------------------------
Paul D. Smith <address@hidden> Find some GNU make tips at:
http://www.gnu.org http://make.mad-scientist.net
"Please remain calm...I may be mad, but I am a professional." --Mad Scientist