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Re: a question about $(call function
From: |
Paul Smith |
Subject: |
Re: a question about $(call function |
Date: |
Sun, 12 Jun 2011 16:37:40 -0400 |
On Sat, 2011-06-11 at 14:49 +0430, ali hagigat wrote:
> In the following example with make, 3.81 why var2 is aba?
>
> kk=$(1)00
> aba=$(1)11
> var1=kk
> $(call var1)=aba
> var2=$(call $(call var1),pp)
> all: ;
> $(warning var2=$(var2))
>
> makefile27:7: var2=aba
Because you have "$(call var1)=aba" and $(call var1) expands kk, so this
statement expands to "kk=aba".
--
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Paul D. Smith <address@hidden> Find some GNU make tips at:
http://www.gnu.org http://make.mad-scientist.net
"Please remain calm...I may be mad, but I am a professional." --Mad Scientist