help-octave
[Top][All Lists]
Advanced

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: drawing line in graph


From: Paul Kienzle
Subject: Re: drawing line in graph
Date: Mon, 4 Mar 2002 09:19:52 -0500

This:

 plot(rand(2,100),rand(2,100),";;")

is a lot faster than this:

 plot(rand(2,1),rand(2,1),";;");
 hold on; for i=2:100, plot(rand(2,1),rand(2,1),";;"); end; hold off

Paul Kienzle
address@hidden

On Sun, Mar 03, 2002 at 02:07:57PM +0100, Davide Cavallari wrote:
> On Sun, Mar 03, 2002 at 11:55:14AM +0100, Davide Cavallari wrote:
> > How can  I draw a  line between  2 points? 
> 
> ehm, that  was en error,  I can  draw a segment!  However, I need  to draw
> multiple segments on the same graph. For example, I have 4 points:
> 
> a=[0,0]; b=[2,2]; c[4,0]; d=[4,2]
> 
> and I want to join b with a and c and d. How can I do this?
> 
> Finally, I will need to join this way a lot of points (I need to represent
> graphically a Kohonen Self-Organizing Map). Is  there a way to simply join
> a pair of points, then another pair and so, all on the same graph? In this
> way infact I could use an iterative procedure.
> -- 
> Cheers,
>     Davide Cavallari                
> Blessed be those who initiate lively discussions with the hopelessly mute,
> for they shall be know as Dentists.
> 
> 
> 
> -------------------------------------------------------------
> Octave is freely available under the terms of the GNU GPL.
> 
> Octave's home on the web:  http://www.octave.org
> How to fund new projects:  http://www.octave.org/funding.html
> Subscription information:  http://www.octave.org/archive.html
> -------------------------------------------------------------
> 



-------------------------------------------------------------
Octave is freely available under the terms of the GNU GPL.

Octave's home on the web:  http://www.octave.org
How to fund new projects:  http://www.octave.org/funding.html
Subscription information:  http://www.octave.org/archive.html
-------------------------------------------------------------



reply via email to

[Prev in Thread] Current Thread [Next in Thread]