Arguments out?

[Vic Norton]

I'm afraid I don't understand how output arguments work in octave. I 
am writing a routine, simp, to solve the linear programming problem

   minimize
                 c * x
   subject to
               A * x = b
          prod( x(I) >= 0 ) == 1

The function should look like this

    [ x, pi, fail ] = simp( A, b, c, I )    #  pi * b == c * x

with nargout = 3. But, for nargout = 0, 1, 2, I would like it to return

    simp( A, b, c, I )                  #  nargout == 0, return ans = x
    x = simp( A, b, c, I )              #  nargout == 1
    [ x, fail ] = simp( A, b, c, I )    #  nargout == 2

Is this possible? Or do I have to use

    [ x, fail, pi ] = simp( A, b, c, I )

in order that the nargout = 0, 1, 2 returns be what I want?


Regards,

Vic

--
*---* mailto:address@hidden
|     Victor Thane Norton, Jr.
|     Mathematician and Motorcyclist
|     phone: 419-353-3399
*---* http://vic.norton.name



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