Re: Difference between normal_rnd (m,v, n,n) and randn (n)

[Henry F. Mollet]

I have to check what exactly people say when they say that they use a
triangular distribution. I surmise that the probability density function in
the range [0,1] increases linearly from some value at 0 to a maximum at an
intermediate value (might be in the middle of the range) and then decreases
linearly to some value at 1.  I'll try to modify what you gave below to get
something that looks like a triangle. Thanks.
Henry


on 3/4/04 12:04 PM, Quentin Spencer at address@hidden wrote:

> Henry F. Mollet wrote:
> 
>> The only one I haven't found yet is a triangular distribution.
>>  
>> 
> Do you mean a distribution whose density is  f(x)=2x in the range [0,1]?
> This can be generated by taking the square root of a uniformly
> distributed random variable. To test this, try
> 
> N = some large number
> x = rand(1,N);
> hist(sqrt(x));
> 
> 
> -Quentin



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