Re: Forcing Variable Outputs

[Geordie McBain]

Does this do what you want?

  function varargout = fxn1 (varargin)
    varargout = fxn2 (varargin{:});
  endfunction

  function varargout = fxn2 (varargin)
    varargout = {varargin};
  endfunction

I see:

octave2.9:1> a = fxn1 (1)
a = 1
octave2.9:2> [a, b] = fxn1 (1, 2)
a = 1
b = 2


On Tue, 2006-03-28 at 20:53 -0500, Bill Denney wrote:
> I have a function that I want to force to have a variable number of output 
> arguements based on its calling function's number of output arguements. 
> In other words, I want to do something like
> 
> function [varargout] = fxn1(varargin)
> 
>    varargout{:} = fxn2(varargin{:});
> 
> endfunction
> 
> and I want fxn2 to see the same number of output arguements that fxn1 
> sees.
> 
> I thought of initializing varargout like
> 
> varargout = cell(1, nargout);
> 
> but that didn't work.  Is there a way to do this?
> 
> Bill
> 



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