Re: A * x = 0 for singular matrix

[lipschitz82]

By ~= 0 I mean approximately singular. It is singular up to my level of tolerance. 

Thanks for the suggestion,
G.R.

On 2/23/07, Quentin Spencer <address@hidden> wrote:

lipschitz82 wrote:
> I need to calculate the vector s.t. Ax = 0, for det(A) ~= 0. I've
> looked at the documentation, octave-forge, etc. but I couldn't find a
> routine for doing this. Matrix A is pretty big, ie. in the hundreds,
> but I also have a lot of computer time if the available routine is slow.

Your subject line says A is singular, but your description of the
problem says det(A)~=0, which means it is not singular, so which is it?
Assuming A is singular, the "null" function will compute a set of basis
vectors for the null space of A.

Quentin