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Re: varargout{:} = func() ?
From: |
Jaroslav Hajek |
Subject: |
Re: varargout{:} = func() ? |
Date: |
Wed, 24 Feb 2010 06:01:06 +0100 |
On Wed, Feb 24, 2010 at 3:47 AM, FW <address@hidden> wrote:
>> v =
>> []
>> []
>> []
>>
>>>> v{:} = rand(1,2)
>> v = [1x2 double]
>>
>> My impression is that this isn't very new, but as I've always found some of
>> how Matlab handles cells to be counter intuitive (if not misleading), so I'm
>> not in the habit of using this notation.
>
> Do you have a way of returning a cell array of results that packages
> up the variable outputs? That is the reasonable problem this notation
> solves, even if the syntax is not so reasonable.
>
v = cell (expected_nargout, 1);
[v{:}] = func (...);
it's necessary to pre-allocate the cell array because in the second
line, the number of output values (nargout) should be determined
before func () is called. That is why [v{:}] doesn't work if v doesn't
exist.
If you have something else on mind, then please clarify.
--
RNDr. Jaroslav Hajek, PhD
computing expert & GNU Octave developer
Aeronautical Research and Test Institute (VZLU)
Prague, Czech Republic
url: www.highegg.matfyz.cz
Re: varargout{:} = func() ?, Jaroslav Hajek, 2010/02/23
- Re: varargout{:} = func() ?, forkandwait, 2010/02/24
- Re: varargout{:} = func() ?, John W. Eaton, 2010/02/24
- Re: varargout{:} = func() ?, forkandwait, 2010/02/24
- Re: varargout{:} = func() ?, John W. Eaton, 2010/02/24
- Re: varargout{:} = func() ?, forkandwait, 2010/02/24
Re: varargout{:} = func() ?, Jaroslav Hajek, 2010/02/24