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Re: svd
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From: |
CdeMills |
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Subject: |
Re: svd |
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Date: |
Tue, 15 Jun 2010 07:48:49 -0700 (PDT) |
In the first case, the answer is a diagonal matrix with data on the main
diagonal only, comprising 1000 results. In the second case, you have 2
millions (2 x 1000 x 1000) results to compute and store. This should be a
good starting point to explain the timing difference.
Regards
Pascal
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- svd, Dmitri A. Sergatskov, 2010/06/13
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- Re: svd, Jaroslav Hajek, 2010/06/14
- Re: svd,
CdeMills <=