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Re: Help

From: Liam Groener
Subject: Re: Help
Date: Sat, 18 Feb 2012 14:41:32 -0800

Sent from my iPad

On Feb 18, 2012, at 12:42 PM, Appau Joseph <address@hidden> wrote:

> How do I evaluate the series 
> 12+22+32+...+1002
Since this is an arithmetic series, the sum is just the average of the first 
and last element times the number of elements:

S = (12 + 1002)*100/2

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