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## i+++j

**From**: |
Muhali |

**Subject**: |
i+++j |

**Date**: |
Wed, 29 Feb 2012 12:48:33 -0800 (PST) |

In pushing my math limits, I stumbled upon
i+++j
octave apparently does this:
octave:> i=j=0
i = 0
octave:> k=i+++j; disp([i j k]) ;
1 0 0
octave:> k=i+++j; disp([i j k]) ;
2 0 1
that is, doing first i++ and then adding j which always remains 0. It could
be the other way round (leaving i and increasing j). So, is there a
rationale for this, and should it not be as in matlab which does nothing,
not even complain, no matter how many additional +'s are used?
--
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