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| From: | dirac |
| Subject: | Re: detecting a sign change in a vector |
| Date: | Tue, 5 Feb 2013 03:30:40 -0800 (PST) |
I had to do a bit of interpolation because the value the function takes between two indices either side of zero was huge. This was a problem with the adaptive step size of the Runge-Kutta I implemented and the fact that the steep gradient of the function. I fixed it by hard wiring the step size and the interpolation suggested. Again thanks! Martin ----- Still learning everyday. -- View this message in context: http://octave.1599824.n4.nabble.com/detecting-a-sign-change-in-a-vector-tp4649327p4649506.html Sent from the Octave - General mailing list archive at Nabble.com.
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