Is this correct?

[Macy]

This is a problem 'interpretting' a swept tone in octave.
The fft plot looks like it's too wide a spectrum.

Not sure why, or what is going on here.
The idea was to sweep from 300MHz to 400MHz: and doing so I expected ONLY 
energy in that spectral range, after all it is a slow sweep. 

fixed tone as a reference:
fc=300e6;dt=1/10/fc;N=120000;
t=[0:1:N-1]*dt;
sig=sin(2*pi()*fc*t);
b=fft(sig)/N;
produces a plot with appropriate spike(s)

ok now I wish to sweep the tone from 300MHz up to 400MHz
sig=sin(2*pi()*1e6*(300+100*([0:N-1])/N).*t);
which should make a tone sweep from 300MHz up to 400MHz, right?
when I plotted the fft, it looked like the energy went from 300MHz up to 500MHz 
??!!

so went back and plotted
plot(t(1:100),sig(1:100));
hold on;
plot(t(1:100),sig(end-100+1:end))
hold off;
is ok, time range held the same just for 'marking'

The frequency did indeed look like 300MHz at the low end and high at the end, 
like almost 400MHz
If go from 400MHz down to 300MHz: 
sig=sin(2*pi()*1e6*(400-100*([0:N-1])/N).*t);
then the fft appears to go from 400MHz down to 200MHz ??!!

What I'm missing is why this is NOT equivalent. the start determines an EXACT 
edge and the ending frequency becomes twice its frequency. What?

The implication to me is that there is energy in those bands, else the fft 
would NOT show it. This is boggling my mind. The implication is that a low pass 
filter will act differently upon a low to high vs a high to low chirp. Perhaps 
the sweep was not as slow as I thought. something else to check. I'll check 
both premises soon, but right now I'm having difficulty wrapping my head about 
these results. 

Are they correct? Is this right?