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[igraph] how to create instance of igraph.Edge in Python and get to the


From: Stefan Reitz
Subject: [igraph] how to create instance of igraph.Edge in Python and get to the value of 'label'-attribute of an edge
Date: Fri, 12 Dec 2008 16:05:13 +0100

Hello,

 

I keep getting errors when trying to create an instance of igraph.Edge

 

import igraph

 

ig = igraph.Graph()

MenueGraph = ig.Read("C:\\Dokumente und Einstellungen\\reitz\\Eigene Dateien\\S1nn Projekte\\UHV\\sprach test\\UHV_Tree_Test\\UHV_Tree_Test\\src\\MenueStrukturUHV_nur_CallStacks.gml", "gml")

 

[everything fine until I get to the nexst line:]

 

ie = igraph.Edge()

à TypeError: cannot create 'igraph.Edge' instances

 

I am trying to get to the attributes of single edges.

 

I am writing test software to automatically test a menu structure. For this to work, the edges must provide the information about the conditions for taking a particular path. So far igraph is nicely providing the shortest paths from beginning to end condition, but I just can’t get to the .gml file’s ‘label’-attribute of any given edge. (I take it that this ‘label’-attribute would be the same one

 

edgeattribs = MenueGraph.edge_attributes()

print edgeattribs

à ['label', 'LabelGraphics', 'edgeAnchor', 'graphics']

 

mentions.)

 

 

Please suggest a way to get to the value of the ‘label’-attribute.

 

 

Mit freundlichen Grüßen / Kind regards

Stefan Reitz 

Test Engineer

Tel:       +49 / 711 / 901 219-97

Fax:      +49 / 711 / 901 219-29

E-Mail address@hidden

www.s1nn.de

 

 

S1nn GmbH & Co. KG

Entennest 1, D-73730 Esslingen

Geschäftsführer:           Philipp Popov, Andreas Heim

Sitz der Gesellschaft:   Esslingen am Neckar

Registergericht:            Stuttgart, HRA 212366

Ust.-Id.-Nr./VAT-No.:     DE238986211

 

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