Re: [igraph] a problem with simplify()

[Gábor Csárdi]

Just for the records, this version works with both kind of indexing:

delete.edges(g, E(g)[is.loop(g)])

Gabor

On Thu, Oct 21, 2010 at 7:06 PM, Tamas Nepusz <address@hidden> wrote:
>> Definitely, because your code does not take into account that edges are 
>> reindexed after every deletion. I'd go for delete.edges(g, seq(0, 
>> ecount(g)-1)[is.loop(g)])
> Or, even better: delete.edges(g, which(is.loop(g))-1) if your igraph version 
> uses 0-based indexing. Note that  the R interface of igraph 0.6 has recently 
> switched to 1-based indexing, so if you installed igraph 0.6 in the last few 
> days, you don't have to subtract 1.
>
> --
> T.
>
>
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-- 
Gabor Csardi <address@hidden>     UNIL DGM